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pandas.core.groupby.GroupBy.tail

GroupBy.tail(n=5)[source]

Returns last n rows of each group

Essentially equivalent to .apply(lambda x: x.tail(n)), except ignores as_index flag.

Examples

>>> df = pd.DataFrame([['a', 1], ['a', 2], ['b', 1], ['b', 2]],
                      columns=['A', 'B'])
>>> df.groupby('A').tail(1)
   A  B
1  a  2
3  b  2
>>> df.groupby('A').head(1)
   A  B
0  a  1
2  b  1
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